((2x-3)/5)-7=0

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Solution for ((2x-3)/5)-7=0 equation: 



((2x-3)/5)-7=0

We multiply all the terms by the denominator


((2x-3)-7*5)=0



We calculate terms in parentheses: +((2x-3)-7*5), so:

(2x-3)-7*5

We add all the numbers together, and all the variables

(2x-3)-35

We get rid of parentheses

2x-3-35

We add all the numbers together, and all the variables

2x-38

Back to the equation:

+(2x-38)



We get rid of parentheses

2x-38=0

We move all terms containing x to the left, all other terms to the right

2x=38

x=38/2

x=19

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