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((2x-1)/3)-((x-5)/6)=(x-3)/4
We move all terms to the left:
((2x-1)/3)-((x-5)/6)-((x-3)/4)=0
We calculate fractions
8x/()+(-4x)/()+(-6x)/()=0
We multiply all the terms by the denominator
8x+(-4x)+(-6x)=0
We get rid of parentheses
8x-4x-6x=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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