((2x+4)/6)-2=4

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Solution for ((2x+4)/6)-2=4 equation: 



((2x+4)/6)-2=4

We move all terms to the left:

((2x+4)/6)-2-(4)=0

We add all the numbers together, and all the variables

((2x+4)/6)-6=0

We multiply all the terms by the denominator


((2x+4)-6*6)=0



We calculate terms in parentheses: +((2x+4)-6*6), so:

(2x+4)-6*6

We add all the numbers together, and all the variables

(2x+4)-36

We get rid of parentheses

2x+4-36

We add all the numbers together, and all the variables

2x-32

Back to the equation:

+(2x-32)



We get rid of parentheses

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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