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((2x+3)/2)=x-1
We move all terms to the left:
((2x+3)/2)-(x-1)=0
We get rid of parentheses
((2x+3)/2)-x+1=0
We multiply all the terms by the denominator
((2x+3)-x*2)+1*2)=0
We calculate terms in parentheses: +((2x+3)-x*2), so:We add all the numbers together, and all the variables
(2x+3)-x*2
Wy multiply elements
(2x+3)-2x
We get rid of parentheses
2x-2x+3
We add all the numbers together, and all the variables
3
Back to the equation:
+(3)
=0
x=0/1
x=0
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