((2x+3)+(2x+3))+(3x-1)=180

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Solution for ((2x+3)+(2x+3))+(3x-1)=180 equation: 



((2x+3)+(2x+3))+(3x-1)=180

We move all terms to the left:

((2x+3)+(2x+3))+(3x-1)-(180)=0

We get rid of parentheses

((2x+3)+(2x+3))+3x-1-180=0



We calculate terms in parentheses: +((2x+3)+(2x+3)), so:

(2x+3)+(2x+3)

We get rid of parentheses

2x+2x+3+3

We add all the numbers together, and all the variables

4x+6

Back to the equation:

+(4x+6)



We add all the numbers together, and all the variables

3x+(4x+6)-181=0

We get rid of parentheses

3x+4x+6-181=0

We add all the numbers together, and all the variables

7x-175=0

We move all terms containing x to the left, all other terms to the right

7x=175

x=175/7

x=25

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