((2x+12)/7)=3x-1

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Solution for ((2x+12)/7)=3x-1 equation: 



((2x+12)/7)=3x-1

We move all terms to the left:

((2x+12)/7)-(3x-1)=0

We get rid of parentheses

((2x+12)/7)-3x+1=0

We multiply all the terms by the denominator


((2x+12)-3x*7)+1*7)=0



We calculate terms in parentheses: +((2x+12)-3x*7), so:

(2x+12)-3x*7

Wy multiply elements

(2x+12)-21x

We get rid of parentheses

2x-21x+12

We add all the numbers together, and all the variables

-19x+12

Back to the equation:

+(-19x+12)



We add all the numbers together, and all the variables

(-19x+12)=0

We get rid of parentheses

-19x+12=0

We move all terms containing x to the left, all other terms to the right

-19x=-12

x=-12/-19

x=12/19

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