((2x+1)+(x+1))-(3x+1)=

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Solution for ((2x+1)+(x+1))-(3x+1)= equation:


Simplifying
((2x + 1) + (x + 1)) + -1(3x + 1) = 0

Reorder the terms:
((1 + 2x) + (x + 1)) + -1(3x + 1) = 0

Remove parenthesis around (1 + 2x)
(1 + 2x + (x + 1)) + -1(3x + 1) = 0

Reorder the terms:
(1 + 2x + (1 + x)) + -1(3x + 1) = 0

Remove parenthesis around (1 + x)
(1 + 2x + 1 + x) + -1(3x + 1) = 0

Reorder the terms:
(1 + 1 + 2x + x) + -1(3x + 1) = 0

Combine like terms: 1 + 1 = 2
(2 + 2x + x) + -1(3x + 1) = 0

Combine like terms: 2x + x = 3x
(2 + 3x) + -1(3x + 1) = 0

Remove parenthesis around (2 + 3x)
2 + 3x + -1(3x + 1) = 0

Reorder the terms:
2 + 3x + -1(1 + 3x) = 0
2 + 3x + (1 * -1 + 3x * -1) = 0
2 + 3x + (-1 + -3x) = 0

Reorder the terms:
2 + -1 + 3x + -3x = 0

Combine like terms: 2 + -1 = 1
1 + 3x + -3x = 0

Combine like terms: 3x + -3x = 0
1 + 0 = 0
1 = 0

Solving
1 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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