((2x)/5)=((x-2)/10)

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Solution for ((2x)/5)=((x-2)/10) equation: 


x in (-oo:+oo)

(2*x)/5 = (x-2)/10 // - (x-2)/10

(2*x)/5-((x-2)/10) = 0

(-1*(x-2))/10+(2*x)/5 = 0

(-1*5*(x-2))/(5*10)+(2*10*x)/(5*10) = 0

2*10*x-1*5*(x-2) = 0

15*x+10 = 0

(15*x+10)/(5*10) = 0

(15*x+10)/(5*10) = 0 // * 5*10

15*x+10 = 0

15*x+10 = 0 // - 10

15*x = -10 // : 15

x = -10/15

x = -2/3

x = -2/3

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