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((2x)/(x+1))+4x=6
We move all terms to the left:
((2x)/(x+1))+4x-(6)=0
Domain of the equation: (x+1))!=0We add all the numbers together, and all the variables
x∈R
4x+(2x/(x+1))-6=0
We multiply all the terms by the denominator
4x*(x+1))+(2x-6*(x+1))=0
We multiply parentheses
4x*(x+1))+(2x-6x-=0
We add all the numbers together, and all the variables
-6x+4x*(x+1))+(2x=0
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