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b*((2*b-(5*y))/2)-(b*((7*b-(7*y))/2)) = 0
b*((2*b-5*y)/2)-(b*((7*b-7*y)/2)) = 0
(b*(2*b-5*y))/2+(-1*b*(7*b-7*y))/2 = 0
b*(2*b-5*y)-1*b*(7*b-7*y) = 0
2*b*y-5*b^2 = 0
(2*b*y-5*b^2)/2 = 0
(2*b*y-5*b^2)/2 = 0 // * 2
2*b*y-5*b^2 = 0
x belongs to the empty set
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