((2a-a)/(3-5))=(1a)/-2

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Solution for ((2a-a)/(3-5))=(1a)/-2 equation: 


a in (-oo:+oo)

(2*a-a)/(3-5) = (1*a)/(-2) // - (1*a)/(-2)

(2*a-a)/(3-5)-((1*a)/(-2)) = 0

(2*a-a)/(3-5)-(a/(-2)) = 0

a/(-2)+a/2 = 0

(2*a)/(-2*2)+(-2*a)/(-2*2) = 0

2*a-2*a = 0

0 = 0

0/(-2*2) = 0

0/(-2*2) = 0 // * -2*2

0 = 0

0 = 0

a należy do R

a in (-oo:+oo)

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