((1y+z)+(10+-0.2y+-0.02z))=500

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Solution for ((1y+z)+(10+-0.2y+-0.02z))=500 equation:


Simplifying
((1y + z) + (10 + -0.2y + -0.02z)) = 500

Remove parenthesis around (1y + z)
(1y + z + (10 + -0.2y + -0.02z)) = 500

Remove parenthesis around (10 + -0.2y + -0.02z)
(1y + z + 10 + -0.2y + -0.02z) = 500

Reorder the terms:
(10 + 1y + -0.2y + z + -0.02z) = 500

Combine like terms: 1y + -0.2y = 0.8y
(10 + 0.8y + z + -0.02z) = 500

Combine like terms: z + -0.02z = 0.98z
(10 + 0.8y + 0.98z) = 500

Remove parenthesis around (10 + 0.8y + 0.98z)
10 + 0.8y + 0.98z = 500

Solving
10 + 0.8y + 0.98z = 500

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + 0.8y + -10 + 0.98z = 500 + -10

Reorder the terms:
10 + -10 + 0.8y + 0.98z = 500 + -10

Combine like terms: 10 + -10 = 0
0 + 0.8y + 0.98z = 500 + -10
0.8y + 0.98z = 500 + -10

Combine like terms: 500 + -10 = 490
0.8y + 0.98z = 490

Add '-0.98z' to each side of the equation.
0.8y + 0.98z + -0.98z = 490 + -0.98z

Combine like terms: 0.98z + -0.98z = 0.00
0.8y + 0.00 = 490 + -0.98z
0.8y = 490 + -0.98z

Divide each side by '0.8'.
y = 612.5 + -1.225z

Simplifying
y = 612.5 + -1.225z

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