((13x-35)+(5x-19)=(2x+14))

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Solution for ((13x-35)+(5x-19)=(2x+14)) equation: 



((13x-35)+(5x-19)=(2x+14))

We move all terms to the left:

((13x-35)+(5x-19)-((2x+14)))=0



We calculate terms in parentheses: +((13x-35)+(5x-19)-((2x+14))), so:

(13x-35)+(5x-19)-((2x+14))

We get rid of parentheses

13x+5x-((2x+14))-35-19



We calculate terms in parentheses: -((2x+14)), so:

(2x+14)

We get rid of parentheses

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

18x-(2x+14)-54

We get rid of parentheses

18x-2x-14-54

We add all the numbers together, and all the variables

16x-68

Back to the equation:

+(16x-68)



We get rid of parentheses

16x-68=0

We move all terms containing x to the left, all other terms to the right

16x=68

x=68/16

x=4+1/4

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