((1/3))(9x-3)=-10

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Solution for ((1/3))(9x-3)=-10 equation: 



((1/3))(9x-3)=-10

We move all terms to the left:

((1/3))(9x-3)-(-10)=0



Domain of the equation: 3))(9x-3)!=0

x∈R



We add all the numbers together, and all the variables

((+1/3))(9x-3)-(-10)=0

We add all the numbers together, and all the variables

((+1/3))(9x-3)+10=0

We multiply all the terms by the denominator


((+1+10*3))(9x-3)=0



We calculate terms in parentheses: +((+1+10*3))(9x-3), so:

(+1+10*3))(9x-3

We add all the numbers together, and all the variables

31)(9x-3

Back to the equation:

+(31)(9x-3)



We multiply parentheses

279x-93=0

We move all terms containing x to the left, all other terms to the right

279x=93

x=93/279

x=1/3

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