((0.1+x)(0.1+x))/(0.5-x)=0.220

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Solution for ((0.1+x)(0.1+x))/(0.5-x)=0.220 equation: 



((0.1+x)(0.1+x))/(0.5-x)=0.220

We move all terms to the left:

((0.1+x)(0.1+x))/(0.5-x)-(0.220)=0



Domain of the equation: (0.5-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-0.5

x!=-0.5/-1

x!=0.5/1

x∈R



We add all the numbers together, and all the variables

((x+0.1)(x+0.1))/(-1x+0.5)-(0.22)=0

We add all the numbers together, and all the variables

((x+0.1)(x+0.1))/(-1x+0.5)-0.22=0

We multiply parentheses ..

((+x^2+0.1x+0.1x+0.01))/(-1x+0.5)-0.22=0

We multiply all the terms by the denominator


((+x^2+0.1x+0.1x+0.01))-(0.22)*(-1x+0.5)=0



We calculate terms in parentheses: +((+x^2+0.1x+0.1x+0.01)), so:

(+x^2+0.1x+0.1x+0.01)

We get rid of parentheses

x^2+0.1x+0.1x+0.01

We add all the numbers together, and all the variables

x^2+0.2x+0.01

Back to the equation:

+(x^2+0.2x+0.01)



We get rid of parentheses

x^2+0.2x-(0.22)*(-1x+0.5)+0.01=0

We move all terms containing x to the left, all other terms to the right

x^2+0.2x-(0.22)*(-1x+0.5)=-0.01

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