((.4-x)(.4-x))/((.15+x)(.15+x))=4

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Solution for ((.4-x)(.4-x))/((.15+x)(.15+x))=4 equation: 



((.4-x)(.4-x))/((.15+x)(.15+x))=4

We move all terms to the left:

((.4-x)(.4-x))/((.15+x)(.15+x))-(4)=0



Domain of the equation: ((.15+x)(.15+x))!=0

x∈R



We add all the numbers together, and all the variables

((-1x+0.4)(-1x+0.4))/((x+0.15)(x+0.15))-4=0

We multiply parentheses ..

((+x^2-0.4x-0.4x+0.16))/((x+0.15)(x+0.15))-4=0

We multiply all the terms by the denominator


((+x^2-0.4x-0.4x+0.16))-4*((x+0.15)(x+0.15))=0



We calculate terms in parentheses: +((+x^2-0.4x-0.4x+0.16)), so:

(+x^2-0.4x-0.4x+0.16)

We get rid of parentheses

x^2-0.4x-0.4x+0.16

We add all the numbers together, and all the variables

x^2-0.8x+0.16

Back to the equation:

+(x^2-0.8x+0.16)



We get rid of parentheses

x^2-0.8x-4*((x+0.15)(x+0.15))+0.16=0

We multiply parentheses ..

x^2-4*((+x^2+0.15x+0.15x+0.0225))-0.8x+0.16=0

We move all terms containing x to the left, all other terms to the right

x^2-4*((+x^2+0.15x+0.15x+0.0225))-0.8x=-0.16

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