((.1x)/2)+x=1

Solution for ((.1x)/2)+x=1 equation:

((.1x)/2)+x=1

We move all terms to the left:

((.1x)/2)+x-(1)=0

We add all the numbers together, and all the variables

((+.1x)/2)+x-1=0

We add all the numbers together, and all the variables

x+((+.1x)/2)-1=0

We multiply all the terms by the denominator


x*2)+((+.1x)-1*2)=0

We add all the numbers together, and all the variables

x*2)+((+.1x)=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$