((-4(2x-3))/9)-8=-4

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Solution for ((-4(2x-3))/9)-8=-4 equation: 



((-4(2x-3))/9)-8=-4

We move all terms to the left:

((-4(2x-3))/9)-8-(-4)=0

We add all the numbers together, and all the variables

((-4(2x-3))/9)-4=0

We multiply all the terms by the denominator


((-4(2x-3))-4*9)=0



We calculate terms in parentheses: +((-4(2x-3))-4*9), so:

(-4(2x-3))-4*9

We add all the numbers together, and all the variables

(-4(2x-3))-36



We calculate terms in parentheses: +(-4(2x-3)), so:

-4(2x-3)

We multiply parentheses

-8x+12

Back to the equation:

+(-8x+12)



We get rid of parentheses

-8x+12-36

We add all the numbers together, and all the variables

-8x-24

Back to the equation:

+(-8x-24)



We get rid of parentheses

-8x-24=0

We move all terms containing x to the left, all other terms to the right

-8x=24

x=24/-8

x=-3

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