(((x+2)/(x+3))-(x/(x+1)))/2

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Solution for (((x+2)/(x+3))-(x/(x+1)))/2 equation:


D( x )

x+1 = 0

x+3 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:-1) U (-1:+oo)

((x+2)/(x+3)-(x/(x+1)))/2 = 0

((x+2)/(x+3)+(-1*x)/(x+1))/2 = 0

(x+2)/(x+3)+(-1*x)/(x+1) = 0

((x+2)*(x+1))/((x+3)*(x+1))+(-1*x*(x+3))/((x+3)*(x+1)) = 0

(x+2)*(x+1)-1*x*(x+3) = 0

2 = 0

2/((x+3)*(x+1)) = 0

2/((x+3)*(x+1)) = 0 // * (x+3)*(x+1)

2 = 0

2/2 = 0

x belongs to the empty set

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