(((2x)-1)/3)+(((3x)-1)/7)=5

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Solution for (((2x)-1)/3)+(((3x)-1)/7)=5 equation: 



(((2x)-1)/3)+(((3x)-1)/7)=5

We move all terms to the left:

(((2x)-1)/3)+(((3x)-1)/7)-(5)=0

We calculate fractions


(14x-7)/()+(9x-3)/()-5=0

We multiply all the terms by the denominator


(14x-7)+(9x-3)-5*()=0

We add all the numbers together, and all the variables

(14x-7)+(9x-3)=0

We get rid of parentheses

14x+9x-7-3=0

We add all the numbers together, and all the variables

23x-10=0

We move all terms containing x to the left, all other terms to the right

23x=10

x=10/23

x=10/23

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