y^2+4y-12/3y^2+2y+12

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Solution for y^2+4y-12/3y^2+2y+12 equation: 


y in (-oo:+oo)

y^2-((12/3)*y^2)+4*y+2*y+12 = 0

y^2-4*y^2+4*y+2*y+12 = 0

6*y-3*y^2+12 = 0

DELTA = 6^2-(-3*4*12)

DELTA = 180

DELTA > 0

y = (180^(1/2)-6)/(-3*2) or y = (-180^(1/2)-6)/(-3*2)

y = (6*5^(1/2)-6)/(-6) or y = (-6*5^(1/2)-6)/(-6)

y in { (6*5^(1/2)-6)/(-6), (-6*5^(1/2)-6)/(-6) }

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