9a-3(2a+5)=7(a-1)a+10

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Solution for 9a-3(2a+5)=7(a-1)a+10 equation: 



9a-3(2a+5)=7(a-1)a+10

We move all terms to the left:

9a-3(2a+5)-(7(a-1)a+10)=0

We multiply parentheses

9a-6a-(7(a-1)a+10)-15=0



We calculate terms in parentheses: -(7(a-1)a+10), so:

7(a-1)a+10

We multiply parentheses

7a^2-7a+10

Back to the equation:

-(7a^2-7a+10)



We add all the numbers together, and all the variables

3a-(7a^2-7a+10)-15=0

We get rid of parentheses

-7a^2+3a+7a-10-15=0

We add all the numbers together, and all the variables

-7a^2+10a-25=0

a = -7; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·(-7)·(-25)
Δ = -600
Delta is less than zero, so there is no solution for the equation

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