9(x-2)+x=10(x-3)+12

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Solution for 9(x-2)+x=10(x-3)+12 equation: 


Simplifying
9(x + -2) + x = 10(x + -3) + 12

Reorder the terms:
9(-2 + x) + x = 10(x + -3) + 12
(-2 * 9 + x * 9) + x = 10(x + -3) + 12
(-18 + 9x) + x = 10(x + -3) + 12

Combine like terms: 9x + x = 10x
-18 + 10x = 10(x + -3) + 12

Reorder the terms:
-18 + 10x = 10(-3 + x) + 12
-18 + 10x = (-3 * 10 + x * 10) + 12
-18 + 10x = (-30 + 10x) + 12

Reorder the terms:
-18 + 10x = -30 + 12 + 10x

Combine like terms: -30 + 12 = -18
-18 + 10x = -18 + 10x

Add '18' to each side of the equation.
-18 + 18 + 10x = -18 + 18 + 10x

Combine like terms: -18 + 18 = 0
0 + 10x = -18 + 18 + 10x
10x = -18 + 18 + 10x

Combine like terms: -18 + 18 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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