7-3(1x+2)+4x+40=

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Solution for 7-3(1x+2)+4x+40= equation:


Simplifying
7 + -3(1x + 2) + 4x + 40 = 0

Reorder the terms:
7 + -3(2 + 1x) + 4x + 40 = 0
7 + (2 * -3 + 1x * -3) + 4x + 40 = 0
7 + (-6 + -3x) + 4x + 40 = 0

Reorder the terms:
7 + -6 + 40 + -3x + 4x = 0

Combine like terms: 7 + -6 = 1
1 + 40 + -3x + 4x = 0

Combine like terms: 1 + 40 = 41
41 + -3x + 4x = 0

Combine like terms: -3x + 4x = 1x
41 + 1x = 0

Solving
41 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-41' to each side of the equation.
41 + -41 + 1x = 0 + -41

Combine like terms: 41 + -41 = 0
0 + 1x = 0 + -41
1x = 0 + -41

Combine like terms: 0 + -41 = -41
1x = -41

Divide each side by '1'.
x = -41

Simplifying
x = -41

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