5cos(3.14/12t)

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Solution for 5cos(3.14/12t) equation: 


t in (-oo:+oo)

5*cos((3.14/12)*t) = 0

cos((3.14/12)*t) = 0

cos((3.14/12)*t) = 0  <=>  (3.14/12)*t = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

(3.14/12)*t-t_1 = 0

0.26166667*t-t_1 = 0 // + t_1

0.26166667*t = t_1 // : 0.26166667

t = t_1/0.26166667

t = 3.821656*t_1

t = 3.821656*pi*k_1+pi/2 i k_1 należy do I

5*cos((3.14/12)*t) = 0  <=>  5 = 0 or 5*cos((3.14/12)*t) = 0  <=>  cos((3.14/12)*t) = 0

t = 3.821656*pi*k_1+pi/2

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