5+i/(4-4i)^2

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Solution for 5+i/(4-4i)^2 equation: 


D( i )

(4-(4*i))^2 = 0

(4-(4*i))^2 = 0

(4-(4*i))^2 = 0

(4-4*i)^2 = 0

4-4*i = 0 // - 4

-4*i = -4 // : -4

i = -4/(-4)

i = 1

i in (-oo:1) U (1:+oo)

i/((4-(4*i))^2)+5 = 0

i/((4-4*i)^2)+5 = 0

i/((4-4*i)^2)+(5*(4-4*i)^2)/((4-4*i)^2) = 0

5*(4-4*i)^2+i = 0

80*i^2-159*i+80 = 0

80*i^2-159*i+80 = 0

80*i^2-159*i+80 = 0

DELTA = (-159)^2-(4*80*80)

DELTA = -319

DELTA < 0

1 = 0

1/((4-4*i)^2) = 0

1/((4-4*i)^2) = 0 // * (4-4*i)^2

1 = 0

i belongs to the empty set

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