3q(2q+7r)=

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Solution for 3q(2q+7r)= equation: 


Simplifying
3q(2q + 7r) = 0
(2q * 3q + 7r * 3q) = 0

Reorder the terms:
(21qr + 6q2) = 0
(21qr + 6q2) = 0

Solving
21qr + 6q2 = 0

Solving for variable 'q'.

Factor out the Greatest Common Factor (GCF), '3q'.
3q(7r + 2q) = 0

Ignore the factor 3.

Subproblem 1
Set the factor 'q' equal to zero and attempt to solve:

Simplifying
q = 0

Solving
q = 0

Move all terms containing q to the left, all other terms to the right.

Simplifying
q = 0

Subproblem 2
Set the factor '(7r + 2q)' equal to zero and attempt to solve:

Simplifying
7r + 2q = 0

Reorder the terms:
2q + 7r = 0

Solving
2q + 7r = 0

Move all terms containing q to the left, all other terms to the right.

Add '-7r' to each side of the equation.
2q + 7r + -7r = 0 + -7r

Combine like terms: 7r + -7r = 0
2q + 0 = 0 + -7r
2q = 0 + -7r
Remove the zero:
2q = -7r

Divide each side by '2'.
q = -3.5r

Simplifying
q = -3.5r
Solution
q = {0, -3.5r}

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