3(y-3)=2y-9+y

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Solution for 3(y-3)=2y-9+y equation: 


Simplifying
3(y + -3) = 2y + -9 + y

Reorder the terms:
3(-3 + y) = 2y + -9 + y
(-3 * 3 + y * 3) = 2y + -9 + y
(-9 + 3y) = 2y + -9 + y

Reorder the terms:
-9 + 3y = -9 + 2y + y

Combine like terms: 2y + y = 3y
-9 + 3y = -9 + 3y

Add '9' to each side of the equation.
-9 + 9 + 3y = -9 + 9 + 3y

Combine like terms: -9 + 9 = 0
0 + 3y = -9 + 9 + 3y
3y = -9 + 9 + 3y

Combine like terms: -9 + 9 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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