3(w+1)=2/7(w-1)

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Solution for 3(w+1)=2/7(w-1) equation: 



3(w+1)=2/7(w-1)

We move all terms to the left:

3(w+1)-(2/7(w-1))=0



Domain of the equation: 7(w-1))!=0

w∈R



We multiply parentheses

3w-(2/7(w-1))+3=0

We multiply all the terms by the denominator


3w*7(w-1))-(2+3*7(w-1))=0

Wy multiply elements

21w^2(w+21w(w=0

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