3(a-4)+2(a+1)=10-5a

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Solution for 3(a-4)+2(a+1)=10-5a equation: 


Simplifying
3(a + -4) + 2(a + 1) = 10 + -5a

Reorder the terms:
3(-4 + a) + 2(a + 1) = 10 + -5a
(-4 * 3 + a * 3) + 2(a + 1) = 10 + -5a
(-12 + 3a) + 2(a + 1) = 10 + -5a

Reorder the terms:
-12 + 3a + 2(1 + a) = 10 + -5a
-12 + 3a + (1 * 2 + a * 2) = 10 + -5a
-12 + 3a + (2 + 2a) = 10 + -5a

Reorder the terms:
-12 + 2 + 3a + 2a = 10 + -5a

Combine like terms: -12 + 2 = -10
-10 + 3a + 2a = 10 + -5a

Combine like terms: 3a + 2a = 5a
-10 + 5a = 10 + -5a

Solving
-10 + 5a = 10 + -5a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5a' to each side of the equation.
-10 + 5a + 5a = 10 + -5a + 5a

Combine like terms: 5a + 5a = 10a
-10 + 10a = 10 + -5a + 5a

Combine like terms: -5a + 5a = 0
-10 + 10a = 10 + 0
-10 + 10a = 10

Add '10' to each side of the equation.
-10 + 10 + 10a = 10 + 10

Combine like terms: -10 + 10 = 0
0 + 10a = 10 + 10
10a = 10 + 10

Combine like terms: 10 + 10 = 20
10a = 20

Divide each side by '10'.
a = 2

Simplifying
a = 2

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