3(5c+4d)+6(d-2c)=

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Solution for 3(5c+4d)+6(d-2c)= equation:


Simplifying
3(5c + 4d) + 6(d + -2c) = 0
(5c * 3 + 4d * 3) + 6(d + -2c) = 0
(15c + 12d) + 6(d + -2c) = 0

Reorder the terms:
15c + 12d + 6(-2c + d) = 0
15c + 12d + (-2c * 6 + d * 6) = 0
15c + 12d + (-12c + 6d) = 0

Reorder the terms:
15c + -12c + 12d + 6d = 0

Combine like terms: 15c + -12c = 3c
3c + 12d + 6d = 0

Combine like terms: 12d + 6d = 18d
3c + 18d = 0

Solving
3c + 18d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-18d' to each side of the equation.
3c + 18d + -18d = 0 + -18d

Combine like terms: 18d + -18d = 0
3c + 0 = 0 + -18d
3c = 0 + -18d
Remove the zero:
3c = -18d

Divide each side by '3'.
c = -6d

Simplifying
c = -6d

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