3(2r+1)=6(r+2)-6

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Solution for 3(2r+1)=6(r+2)-6 equation:


Simplifying
3(2r + 1) = 6(r + 2) + -6

Reorder the terms:
3(1 + 2r) = 6(r + 2) + -6
(1 * 3 + 2r * 3) = 6(r + 2) + -6
(3 + 6r) = 6(r + 2) + -6

Reorder the terms:
3 + 6r = 6(2 + r) + -6
3 + 6r = (2 * 6 + r * 6) + -6
3 + 6r = (12 + 6r) + -6

Reorder the terms:
3 + 6r = 12 + -6 + 6r

Combine like terms: 12 + -6 = 6
3 + 6r = 6 + 6r

Add '-6r' to each side of the equation.
3 + 6r + -6r = 6 + 6r + -6r

Combine like terms: 6r + -6r = 0
3 + 0 = 6 + 6r + -6r
3 = 6 + 6r + -6r

Combine like terms: 6r + -6r = 0
3 = 6 + 0
3 = 6

Solving
3 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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