2x^2+3(x^2-1)=5x(x+1)

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Solution for 2x^2+3(x^2-1)=5x(x+1) equation: 



2x^2+3(x^2-1)=5x(x+1)

We move all terms to the left:

2x^2+3(x^2-1)-(5x(x+1))=0

We multiply parentheses

2x^2+3x^2-(5x(x+1))-3=0



We calculate terms in parentheses: -(5x(x+1)), so:

5x(x+1)

We multiply parentheses

5x^2+5x

Back to the equation:

-(5x^2+5x)



We add all the numbers together, and all the variables

5x^2-(5x^2+5x)-3=0

We get rid of parentheses

5x^2-5x^2-5x-3=0

We add all the numbers together, and all the variables

-5x-3=0

We move all terms containing x to the left, all other terms to the right

-5x=3

x=3/-5

x=-3/5

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