25x(x^2+3x)=2(2x+16)

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Solution for 25x(x^2+3x)=2(2x+16) equation: 



25x(x^2+3x)=2(2x+16)

We move all terms to the left:

25x(x^2+3x)-(2(2x+16))=0

We multiply parentheses

25x^3+75x^2-(2(2x+16))=0



We calculate terms in parentheses: -(2(2x+16)), so:

2(2x+16)

We multiply parentheses

4x+32

Back to the equation:

-(4x+32)



We do not support expression: x^3

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