16y^2-20y=-4

Solution for 16y^2-20y=-4 equation:

16y^2-20y=-4

We move all terms to the left:

16y^2-20y-(-4)=0

We add all the numbers together, and all the variables

16y^2-20y+4=0

a = 16; b = -20; c = +4;
Δ = b2-4ac
Δ = -202-4·16·4
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12}{2*16}=\frac{8}{32}
=1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12}{2*16}=\frac{32}{32}
=1
$