15y^2-25y-10=0

Solution for 15y^2-25y-10=0 equation:

15y^2-25y-10=0

a = 15; b = -25; c = -10;
Δ = b2-4ac
Δ = -252-4·15·(-10)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-35}{2*15}=\frac{-10}{30}
=-1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+35}{2*15}=\frac{60}{30}
=2
$