1+6(1+2b)=3(b-1)-b

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Solution for 1+6(1+2b)=3(b-1)-b equation:


Simplifying
1 + 6(1 + 2b) = 3(b + -1) + -1b
1 + (1 * 6 + 2b * 6) = 3(b + -1) + -1b
1 + (6 + 12b) = 3(b + -1) + -1b

Combine like terms: 1 + 6 = 7
7 + 12b = 3(b + -1) + -1b

Reorder the terms:
7 + 12b = 3(-1 + b) + -1b
7 + 12b = (-1 * 3 + b * 3) + -1b
7 + 12b = (-3 + 3b) + -1b

Combine like terms: 3b + -1b = 2b
7 + 12b = -3 + 2b

Solving
7 + 12b = -3 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
7 + 12b + -2b = -3 + 2b + -2b

Combine like terms: 12b + -2b = 10b
7 + 10b = -3 + 2b + -2b

Combine like terms: 2b + -2b = 0
7 + 10b = -3 + 0
7 + 10b = -3

Add '-7' to each side of the equation.
7 + -7 + 10b = -3 + -7

Combine like terms: 7 + -7 = 0
0 + 10b = -3 + -7
10b = -3 + -7

Combine like terms: -3 + -7 = -10
10b = -10

Divide each side by '10'.
b = -1

Simplifying
b = -1

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