0=n(n-6)(n-9)-n^2(n-14)

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Solution for 0=n(n-6)(n-9)-n^2(n-14) equation: 



0=n(n-6)(n-9)-n^2(n-14)

We move all terms to the left:

0-(n(n-6)(n-9)-n^2(n-14))=0

We add all the numbers together, and all the variables

-(n(n-6)(n-9)-n^2(n-14))=0

We multiply parentheses ..

-(n(+n^2-9n-6n+54)-n^2(n-14))=0



We calculate terms in parentheses: -(n(+n^2-9n-6n+54)-n^2(n-14)), so:

n(+n^2-9n-6n+54)-n^2(n-14)

We multiply parentheses

n^3-9n^2-6n^2-n^2(n-14)+54n

We do not support enpression: n^3

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