-16x^2-48x+256=0

Solution for -16x^2-48x+256=0 equation:

-16x^2-48x+256=0

a = -16; b = -48; c = +256;
Δ = b2-4ac
Δ = -482-4·(-16)·256
Δ = 18688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18688}=\sqrt{256*73}=\sqrt{256}*\sqrt{73}=16\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-16\sqrt{73}}{2*-16}=\frac{48-16\sqrt{73}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+16\sqrt{73}}{2*-16}=\frac{48+16\sqrt{73}}{-32}
$