(x+5)(x^2+7x+1)=0

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Solution for (x+5)(x^2+7x+1)=0 equation:


Simplifying
(x + 5)(x2 + 7x + 1) = 0

Reorder the terms:
(5 + x)(x2 + 7x + 1) = 0

Reorder the terms:
(5 + x)(1 + 7x + x2) = 0

Multiply (5 + x) * (1 + 7x + x2)
(5(1 + 7x + x2) + x(1 + 7x + x2)) = 0
((1 * 5 + 7x * 5 + x2 * 5) + x(1 + 7x + x2)) = 0
((5 + 35x + 5x2) + x(1 + 7x + x2)) = 0
(5 + 35x + 5x2 + (1 * x + 7x * x + x2 * x)) = 0
(5 + 35x + 5x2 + (1x + 7x2 + x3)) = 0

Reorder the terms:
(5 + 35x + 1x + 5x2 + 7x2 + x3) = 0

Combine like terms: 35x + 1x = 36x
(5 + 36x + 5x2 + 7x2 + x3) = 0

Combine like terms: 5x2 + 7x2 = 12x2
(5 + 36x + 12x2 + x3) = 0

Solving
5 + 36x + 12x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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