(4-3c)(7+c+2c^2)=

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Solution for (4-3c)(7+c+2c^2)= equation: 


Simplifying
(4 + -3c)(7 + c + 2c2) = 0

Multiply (4 + -3c) * (7 + c + 2c2)
(4(7 + c + 2c2) + -3c * (7 + c + 2c2)) = 0
((7 * 4 + c * 4 + 2c2 * 4) + -3c * (7 + c + 2c2)) = 0
((28 + 4c + 8c2) + -3c * (7 + c + 2c2)) = 0
(28 + 4c + 8c2 + (7 * -3c + c * -3c + 2c2 * -3c)) = 0
(28 + 4c + 8c2 + (-21c + -3c2 + -6c3)) = 0

Reorder the terms:
(28 + 4c + -21c + 8c2 + -3c2 + -6c3) = 0

Combine like terms: 4c + -21c = -17c
(28 + -17c + 8c2 + -3c2 + -6c3) = 0

Combine like terms: 8c2 + -3c2 = 5c2
(28 + -17c + 5c2 + -6c3) = 0

Solving
28 + -17c + 5c2 + -6c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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