(3x-10)/(x-4)=3

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Solution for (3x-10)/(x-4)=3 equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(3*x-10)/(x-4) = 3 // - 3

(3*x-10)/(x-4)-3 = 0

(3*x-10)/(x-4)+(-3*(x-4))/(x-4) = 0

3*x-3*(x-4)-10 = 0

2 = 0

2/(x-4) = 0

2/(x-4) = 0 // * x-4

2 = 0

2 = 0

x belongs to the empty set

x belongs to the empty set

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