(2x+7)/(x)+(7)/(x+7)=7

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Solution for (2x+7)/(x)+(7)/(x+7)=7 equation: 



(2x+7)/(x)+(7)/(x+7)=7

We move all terms to the left:

(2x+7)/(x)+(7)/(x+7)-(7)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+7)!=0

We move all terms containing x to the left, all other terms to the right

x!=-7

x∈R



We calculate fractions


((2x+7)*(x+7))/(x^2+7x)+7x/(x^2+7x)-7=0



We calculate terms in parentheses: +((2x+7)*(x+7))/(x^2+7x), so:

(2x+7)*(x+7))/(x^2+7x

We add all the numbers together, and all the variables

7x+(2x+7)*(x+7))/(x^2

We multiply all the terms by the denominator


7x*(x^2+(2x+7)*(x+7))

Back to the equation:

+(7x*(x^2+(2x+7)*(x+7)))



We multiply all the terms by the denominator


((7x*(x^2+(2x+7)*(x+7))))*(x^2+7x)+7x-7*(x^2+7x)=0



We calculate terms in parentheses: +((7x*(x^2+(2x+7)*(x+7))))*(x^2+7x), so:

(7x*(x^2+(2x+7)*(x+7))))*(x^2+7x

We add all the numbers together, and all the variables

7x+(7x*(x^2+(2x+7)*(x+7))))*(x^2

Back to the equation:

+(7x+(7x*(x^2+(2x+7)*(x+7))))*(x^2)



We add all the numbers together, and all the variables

7x+(7x+(7x*(x^2+(2x+7)*(x+7))))*x^2-7*(x^2+7x)=0

We multiply parentheses

-7x^2+7x+(7x+(7x*(x^2+(2x+7)*(x+7))))*x^2-49x=0

We add all the numbers together, and all the variables

-7x^2-42x+(7x+(7x*(x^2+(2x+7)*(x+7))))*x^2=0

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