(1/9)^3t+5=1/243^t-6

Solution for (1/9)^3t+5=1/243^t-6 equation:

(1/9)^3t+5=1/243^t-6

We move all terms to the left:

(1/9)^3t+5-(1/243^t-6)=0


Domain of the equation: 9)^3t!=0

t!=0/1

t!=0

t∈R



Domain of the equation: 243^t-6)!=0

t∈R


We add all the numbers together, and all the variables

(+1/9)^3t-(1/243^t-6)+5=0

We get rid of parentheses

(+1/9)^3t-1/243^t+6+5=0

We calculate fractions


((+1*243^t)/9^3t*243^t)+(-9t)/9^3t*243^t)+6+5=0


We calculate terms in parentheses: +((+1*243^t)/9^3t*243^t), so:

(+1*243^t)/9^3t*243^t

We multiply all the terms by the denominator


(+1*243^t)

We get rid of parentheses

1*243^t

Wy multiply elements

243t

Back to the equation:

+(243t)


We multiply all the terms by the denominator


243t*9^3t*243^t)+6+5+(-9t)=0

Wy multiply elements

531441t^5*2-9t)=0

We do not support etpression: t^5