((2x+5)/(x^2+4x-5))+((x-3)/(x-1))=(x)/(x+5)

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Solution for ((2x+5)/(x^2+4x-5))+((x-3)/(x-1))=(x)/(x+5) equation: 



((2x+5)/(x^2+4x-5))+((x-3)/(x-1))=(x)/(x+5)

We move all terms to the left:

((2x+5)/(x^2+4x-5))+((x-3)/(x-1))-((x)/(x+5))=0



Domain of the equation: (x^2+4x-5))!=0

x∈R





Domain of the equation: (x-1))!=0

x∈R





Domain of the equation: (x+5))!=0

x∈R



We calculate fractions


(((2x+5)*(x-1))*x)/((x^2+4x-5))*(x-1))*(x+5)))+(((x-3)*(x^2+4x-5))*x)/((x^2+4x-5))*(x-1))*(x+5)))+(-(x*(x^2+4x-5))*x)/((x^2+4x-5))*(x-1))*(x+5)))=0

We can not solve this equation

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