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x^2-27x+139=0

a = 1; b = -27; c = +139;

Δ = b^{2}-4ac

Δ = -27^{2}-4·1·139

Δ = 173

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{173}}{2*1}=\frac{27-\sqrt{173}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{173}}{2*1}=\frac{27+\sqrt{173}}{2} $

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