x^2+285x-15975=0

Solution for x^2+285x-15975=0 equation:

X^2+285X-15975=0

a = 1; b = 285; c = -15975;
Δ = b2-4ac
Δ = 2852-4·1·(-15975)
Δ = 145125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{145125}=\sqrt{225*645}=\sqrt{225}*\sqrt{645}=15\sqrt{645}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(285)-15\sqrt{645}}{2*1}=\frac{-285-15\sqrt{645}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(285)+15\sqrt{645}}{2*1}=\frac{-285+15\sqrt{645}}{2}
$