x^2+12x-51=0

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Solution for x^2+12x-51=0 equation:



x^2+12x-51=0
a = 1; b = 12; c = -51;
Δ = b2-4ac
Δ = 122-4·1·(-51)
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{87}}{2*1}=\frac{-12-2\sqrt{87}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{87}}{2*1}=\frac{-12+2\sqrt{87}}{2} $

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