n^2+19-4070=0

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Solution for n^2+19-4070=0 equation:

n^2+19-4070=0
We add all the numbers together, and all the variables
n^2-4051=0
a = 1; b = 0; c = -4051;Δ = b2-4acΔ = 02-4·1·(-4051)Δ = 16204The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{16204}=\sqrt{4*4051}=\sqrt{4}*\sqrt{4051}=2\sqrt{4051}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{4051}}{2*1}=\frac{0-2\sqrt{4051}}{2} =-\frac{2\sqrt{4051}}{2} =-\sqrt{4051}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{4051}}{2*1}=\frac{0+2\sqrt{4051}}{2} =\frac{2\sqrt{4051}}{2} =\sqrt{4051}$

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