cos^2(2x)+sin^2(2x)=1

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Solution for cos^2(2x)+sin^2(2x)=1 equation: 


Simplifying
cos2(2x) + sin2(2x) = 1

Remove parenthesis around (2x)
cos2 * 2x + sin2(2x) = 1

Reorder the terms for easier multiplication:
2cos2 * x + sin2(2x) = 1

Multiply cos2 * x
2cos2x + sin2(2x) = 1

Remove parenthesis around (2x)
2cos2x + in2s * 2x = 1

Reorder the terms for easier multiplication:
2cos2x + 2in2s * x = 1

Multiply in2s * x
2cos2x + 2in2sx = 1

Solving
2cos2x + 2in2sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
2cos2x + 2in2sx + -2in2sx = 1 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
2cos2x + 0 = 1 + -2in2sx
2cos2x = 1 + -2in2sx

Divide each side by '2os2x'.
c = 0.5o-1s-2x-1 + -1in2o-1s-1

Simplifying
c = 0.5o-1s-2x-1 + -1in2o-1s-1

Reorder the terms:
c = -1in2o-1s-1 + 0.5o-1s-2x-1

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